Regardless of your particular religious faith, working out the date of Easter in your head for a given year can be an impressive feat.
It's well known that the date for Easter moves around quite a bit, and many people aren't even sure exactly how the Easter date is determined. Despite the rules, it is still possible to mentally calculate the date for a given year.
The Rules
Easter is defined as the first Sunday after the first full moon after the first day of spring in a given year.
It's important to note that, while the official rules for calculating the date for Easter in a given year involve the full moon date and the first day of spring, these are not necessarily tied to the astronomical definitions.
For example, depending on the year, the first day of spring can happen on March 20th or March 21st. For the purposes of Easter calculation, however, the first day of spring is always considered to be March 21st. The first full moon after the first day of spring, then, must always happen after March 21st.
This may seem like a small detail, but it is important to understand the difference between this and the astronomical definition. For example, in 2038, the first day of spring will happen on March 20th, and the next full moon will happen the next day, on March 21st. This full moon doesn't count for Easter calculation, though, because March 21st is always considered to be the first day of spring, so it's the first full moon after that date that is considered.
Finally, if the full moon occurs on a Sunday, then that Sunday is not considered to be Easter, but rather the following Sunday.
So, to sum up the rules for Easter, it falls on the first Sunday after the first full moon after March 21st, the first day of spring. Yes, this is why the Easter date varies so widely from year to year.
You'll need to be able to calculate given dates to determine the day of the week on which a given date falls, so that you'll know when the next Sunday occurs.
Since the first day of spring is always considered to be March 21st, the first full moon must happen by April 19th. The first step in Easter calculations, then, is working out how many days before April 19th the full moon occurs.
The only information you need to start is the year in question. For this part of the tutorial, we'll assume that you're working with a year from 1900 to 2099. Since the moon has a 19-year cycle, you begin by finding out where it is in that 19-year cycle. First, you simply subtract 1900 from the year. Next, assuming you known your multiples of 19, you will subtract the largest multiple of 19 equal to or less than this number.
For example, let's say you're given the year 1988. The first step is easy: 1988 - 1900 = 88. Next, you subtract the largest multiple of 19 which is equal to or less than 88. In this case, that happens to be 76, so 88 - 76 = 12. In other words, 1988 is 12 years into the moon's 19-year Metonic cycle.
The next step is to take this result, and multiply it by 11. If you're worried about multiplying by 11 in your head, you can pick this skill up quickly:
The best part is that the only 2-digit numbers you'll have to deal with in this feat are 10 through 18, so you'll never have to worry about carrying that 1!
After multiplying the number by 11, there are just 2 more steps: Add 5, and then subtract the largest multiple of 30 (due to the moon's roughly 30-day cycle) that is equal to or less than this current total.
Returning to our 1988 example, you'll remember we reduced that to 12. 12 × 11 = 132, and 132 + 5 = 137. The largest multiple of 30 that is equal to or less than 137 is 120, so we subtract 137 - 120 = 17.
The result you get at the end of this process is the number of days before April 19th. In our 1988 example, our result of 17 means that the first full moon after the first day of spring falls on April 2nd (because April 19th - 17 days = April 2nd).
What happens if you get a number of 19 or more? In that case, you think of April 19th as being the same as the imaginary date of March 50th So, if you came up with a total of 24, for example, you'd think of March 50th - 24 days = March 26th.
There are 2 small exceptions. If you begin with a total of 5, you'll get a result of 0, which suggests that the first full moon after the first day of spring is April 19th (0 days before April 19th). You need to make a correcting by moving 1 day back to April 18th, in this case.
The other special case is when you have a total of 16, which gives a result of 1, which suggests that the date is April 18th (1 day before April 19th). This one is also incorrect, and has the same solution; you move 1 more day back to April 17th.
To become comfortable with the full moon calculations before proceeding, go over to the Easter Date For A Given Year Quiz, and click on the Full Moon Date button in the Roman Catholic Easter, 1900-2099 section.
Full Moon to Easter
This is the point at which you'll need to be comfortable with some version of the Day of the Week For Any Date feat, as I mentioned in the previous tab.
Obviously, you'll need to work out the day of the week of date you determined in the previous step. In our 1988 example, we worked out that the first full moon after the first day of spring occurred on April 2nd, 1988. If you know your calendar calculations, you'll be able to work out that this was a Saturday. Obviously, the first Sunday after this date, and therefore Easter, is the very next day, April 3rd, 1988.
One important note at this point: If the full moon date occurs on a Sunday itself, then Easter is the following Sunday.
As another example that will help highlight a few key points, let's work out the date of Easter in 1994. 1994 - 1900 = 94. Subtracting the largest multiple of 19 equal to or less than than gives us 94 - 76 = 18.
Continuing the calculation, we have 18 × 11 = 198, and 198 + 5 = 203. Casting out the largest multiple of 30 from 203 gives us 203 - 180 = 23. 23 days before April 19th, or rather March 50th in this case, is March 27th (March 50th - 23 days = March 27th).
You then work out that March 27th, 1994 is a Sunday. That means that the following Sunday is Easter. March 27th plus 7 days is April 3rd (March 27th + 7 days = March 34th, minus 31 days in March, gives you April 3rd).
At this point, you should practice what you've learned over in the quiz section. Click on the Full Moon and Easter Dates button in the Roman Catholic Easter, 1900-2099 section to become comfortable calculating the full moon and Easter dates together.
The simplest way to start is by asking for the year. Since you have to know some version of the day of the week for any date feat, you can likely use this information to say something about the year. For example, in my Day One routine, you can instantly give the days of the week for Christmas and Halloween that year, as well as which months in that year will have a Friday the 13th.
Such lead-in information given instantly makes a good introduction to calendar feats, but isn't absolutely necessary. In versions of the date feat such as the Doomsday algorithm, which give you a key day for the year, this information can be helpful to work out in advance of the Easter calculations.
You can go directly into the Easter feat, as well. The trick to presenting the Easter calculation before an audience, however, is talking through the major steps while you do the mental calculations.
For example, let's say someone gives you the year 1982. Doing a quick mental subtraction of 82 - 76 (do you remember why?), you get an answer of 6, and can immediately say, In 1982, the moon was 6 years into its 19-year Metonic cycle... As you say that sentence, you can then quickly multiply 6 by 11, getting 66, add 5 to get 71, and subtract 71 - 60 to get 11. Since you know you need to subtract this number from April 19th/March 50th, you can quickly finish by saying, ...which means that April 8th was the date of the first full moon after the first day of spring.
Already, this feat should seem impressive to the audience. At this point, as you already know, you'll have to work out the day of the week for April 8th, 1982 in your head. In this particular case, you should be able to say, Now, April 8th, 1982, was a Thursday, so the following Sunday was only 3 days later, on April 11th, which makes that the date of Easter in 1982!
Have your audience verify the date of Easter in 1982 with Wolfram|Alpha, or a similar source, and they should be suitably impressed!. At that point, you've done the whole Easter feat in front of the audience.
Tips
• Working through the equations while talking is a bit of a challenge, but with practice, it's not that difficult.
• If you can master a day of the week for any date feat, this Easter feat, and giving the phase of the moon for any date, you'll have enough material for a human calendar routine!
• The method you've learned is actually the way to calculate the date for the Roman Catholic Easter. There's an alternative calculation for what's known as Orthodox Easter, celebrated primarily by Greek Orthodox and Russian Orthodox churches, and can sometimes fall on a different date. Once you've mastered the basic calculation, you can learn how to calculate the date for Orthodox Easter here.
Orthodox Easter
Easter has been around longer than the Gregorian calendar, of course, so the original calculations were done using the Julian calendar. Some churches, such as the Russian and Greek Orthodox churches, still use the Julian calendar in their Easter date calculations. This means that the date for Orthodox Easter can sometimes be a different date entirely than the Roman Catholic Easter, sometimes as much as a month apart!
Fortunately, if you can work through the original Easter calculations, calculating the Orthodox Easter date isn't that much different.
To calculate Orthodox Easter, you don't have to start over again. For example, returning to our 1982 example from the Presentation tab, you start by recalling that you calculated the full moon date as 11 days before April 19th/March 50th.
To this number, you need to add 9. Sometimes, this will give you a number larger than 30, in which case you need to subtract 30 from that number. You can then give this new date as the date of the first full moon after the first day of spring in the Julian calendar.
Continuing with our 1982 example, then, you'd add 11 + 9 to get 20, and work out that April 19th/March 50th minus 20 days is March 30th, which is the date of the first full moon after the first day of spring in 1982 is March 30th in the Julian calendar.
To adjust this date to the currently-used Gregorian calendar, you need to add 13 days. The best way to think of this when starting with a date in March is to just add 13, giving the ridiculous date of March 43rd, and then subtract 31 (since March has 31 days), giving April 12th as the Gregorian date of the first full moon after the first day of spring by the standards of the Orthodox Church.
You can quiz yourself on the Orthodox Julian and Gregorian full moon dates by clicking on the Full Moon Dates button in the Orthodox Easter, 1900-2099 section. Because you need to work out the Roman Catholic full moon and Easter dates first, the quiz will ask you about those before asking about the Orthodox Julian and Gregorian full moon dates.
To find the next Sunday after that is also simple. In our 1982 example, you worked out that the Roman Catholic Easter fell on April 11th. Obviously, April 12th is after that, so the Orthodox Easter that year must fall on the next Sunday, which is April 18th. Clicking on the Orthodox Easter Sunday (Christianity) button, your audience can verify that April 18th, 1992 is indeed the date of the Orthodox Easter.
Notice how the use of earlier calculations helps simplify the calculations for the Orthodox Easter, while calculating an entirely different Easter date with a different calendar seems much harder and more impressive to your audience!
You can practice the full feat in the quiz section using the Full Moon and Easter Dates button in the Orthodox Easter, 1900-2099 section. As with the above quiz, you'll be asked about the Roman Catholic full moon and Easter dates first, as you'll need those to make the Orthodox calculations.
Presentation
After giving the Roman Catholic Easter date for a given year, you can point out that there's also an Orthodox Easter date, and that it always isn't the same. If they've verified your given Easter date with Wolfram|Alpha, you can draw your audience's attention to the fact that Wolfram|Alpha has a little blurb that reads, Assuming Easter Sunday (Christianity) | Use Orthodox Easter Sunday (Christianity) instead. Explain to your audience that the Orthodox churches use an older calendar, as opposed to the currently-used one.
Recalling your original calculations for the number of days before April 19th/March 50th, you mentally add 9, subtract 30 if needed, and give this new date (March 30th, in our above 1982 example) as the old-style calendar date for the date of the first full moon after the first day of spring.
Next, mentally add 13 days, subtracting 31 if needed, and give this date (April 12th in our above 1982 example) as the new-style calendar date as the date of the first full moon after the first day of spring.
Finally, work out the date of the following Sunday (April 18th in our above 1982 example) and give that as the Orthodox Easter date. As always, have your audience verify this date for themselves.
Tips
• Similar rules apply to both the Roman Catholic and Orthodox Easter dates. Especially important is the rule that, if a full moon date falls on a Sunday, then it's the following Sunday on which Easter falls.
• Recall from the Easter tab that some dates require adjustments in which you move 1 day back. When returning to the full moon date calculation, you want to add 9 to the unadjusted number of days. For example, 1981 is 5 (81 - 76) years into the Metonic cycle, which results in a total of 0 days before April 19th/March 50th, but you have to adjust 1 day back. When you do the Orthodox calculation, you still want to start with 0 (the unadjusted amount), instead of 1 (the adjusted amount), and add 9 (0 + 9 = 9).
• Being able to calculate both the Roman Catholic and Orthodox Easter dates from 1900 to 2099 is quite an impressive feat. If you're curious about other years, you can learn how to handle other centuries in the next tab!
Other Centuries
Due to all the calculations involved, the easiest thing to do is to stay within the 1900 to 2099 range, as you've already learned. However, if you do wish to calculate Easter for other centuries, this section will give you the tools you'll need.
The 2100s
The easiest extension of the Easter feat is to calculate Easter in the 2100s. As long as you can adjust your favorite day of the week for any date feat for dates in the 2100s, you can calculate Easter dates without any other changes!
Roman Catholic Easter Dates: 1500s through 3000s
The Gregorian calendar was first used in late 1582, so the Roman Catholic Easter date can only be calculated for years going back to 1583.
In the standard version you've learned, you start by subtracting 1900, and then subtracting multiples of 19 in order to learn how far the moon is into its 19-year Metonic cycle. For the following years, you can start by use the corresponding amounts below:
1583 to 1709: subtract 1520
1710 to 1899: subtract 1710
2100 to 2279: subtract 2090
2280 to 2469: subtract 2280
2470 to 2659: subtract 2470
2660 to 2849: subtract 2660
2850 to 3039: subtract 2850
3040 to 3099: subtract 3040
Subtracting these amounts can be made easier by subtracting the hundreds amount, followed by the tens. For example, subtracting 2280 can be done by subtracting 2200 and then subtracting 80. From this point, you reduce the year by multiples of 19 as you learned previously.
The next steps involve multiplying that amount by 11, and then adding 5. Adding 5, however, only works if you're dealing with the 1900s, 2000s, or 2100s. You'll need a different offset for other centuries. The following widget will calculate the required offset for centuries from the 1500s to the 3000s:
The answer you get will be in the form of x = some number and y = some number. x is the first two digits of the century, such as 20 for the 2000s, and y is the offset you'll need to add for years in the given century. For example, if you select the 2300s, you'll get the answer x=23, y=3. This simply means that for years beginning with 23 (x), you'll need to add 3 (y).
Naturally, you shouldn't forget to adjust your day of the week for any date feat calculations for the same centuries.
Orthodox Easter Dates: 1500s through 3000s
Determining how far the moon is into its Metonic cycle is done just as in the previous section. When working in the 1900s and 2000s (and 2100s!), you normally need to add 9 to adjust for the Orthodox date (and subtract 30, if needed).
For other centuries, you may need different numbers. The widget below can calculate the required offsets for any given century:
Similar to the above widget, x represents the first 2 digits of the request century, y is the adjustment for the Julian date, and z is the number of days you need to move ahead to get the Gregorian date.
If you select the 2000s, you'll get 3 very familiar numbers: x=20, y=9, z=13. If you've practiced the Orthodox feat, you'll recall that, for years beginning with 20 (x), you need to add 9 (y) more days (subtracting 30, if needed) back from the Roman Catholic full moon to get the Julian date for the Orthodox full moon. You then need to go 13 (z) days forward to get the equivalent Gregorian calendar date.
If you want to work with the 2300s instead, just select 2300s in the pop-up menu, click the Submit button, and you'll get a result of x=23, y=11, z=16. This means that for any year beginning with 23 (x), you'll need to move back 11 (y) more days from April 19th/March 50th to adjust for the Julian calendar date (remembering to subtract 30, if needed). 16 (z) is the number of days you'll need to move forward from the Julian date to get the corresponding Gregorian date.
You can even calculate the Gregorian offset (z) in your head, if need be. To learn how to do that, read my Changing Calendars Mentally post.
Practice this feat, and you'll have an unusual mental feat ready to astound almost any audience! If you have any questions or comments, please include them in the comments section below.
My fascination is two-fold: How simple can it be made? How powerful can it be made? After researching several methods, many obscure even to those who enjoy calendar calculating, I've managed to merge two astounding versions that bring together the best combination of power and simplicity I've ever run across.
Effect
You start by bringing out a business card with this calendar design:
You then ask someone for the year, and then the month, of their birthday. With no further questions, you're instantly able to fill in the calendar for that month and year. For example, if the person said they were born in 1979 in September, you could quickly fill in the calendar from memory like this:
They can verify your calendar with any outside source, such as Wolfram|Alpha, and see that the calendar you created from memory is 100% accurate!
Even if you've become frustrated trying to master other day of the day of the week for any date formulas, I think you'll like the simplicity and flexibility of this version. You can start learning the method in the next tab!
Year Key
With this method, you ask for the year first, and you're going to calculate a date from it, ranging from 0 to 6.
In many methods, calculating a number from the year is the biggest hurdle, both because of the number of calculations involved, and the fact that many calculations involve increasing the amount represented by the year. In this method, however, the steps are few, and the method always involves making the year number smaller.
When given a year, the first thing you need to do is to break it up into the last 2 digits, which will be referred to as the year from here on out, and the remaining digits, which will be referred to as the century. For exam, if you're given the year 1975, you would think of 75 as the year and 19 as the century.
First, I'll explain the calculations to perform on the 2-digit year, and then I'll explain how to handle the century.
Step 1 - Partition: Split the 2-digit year into a sum, consisting of the largest multiple of 4 equal to or less than the given year, plus a remainder of 1, 2, or 3, if needed.
Example: 75 is split into 72 + 3. 72 is the largest number equal to or less than 75, and 3 is the remainder needed to make it a sum that totals 75.
Step 2 - Modify & solve: Divide the multiple of 4 by 2, and change the plus sign to a minus sign. Once you've modified the problem, the next step is to solve it.
Example: 72 (from 72 + 3 above) ÷ 2 = 36, so 72 + 3 becomes 36 - 3. Solving this, we get 36 - 3 = 33.
Example: The largest multiple of 7 equal to or less than 33 is 28, so we subtract 33 - 28 to get 5.
This may seem like a lot of work at first, but it can be done surprisingly quickly, once you become familiar with it.
Below is a simple widget to show you how this is done with various years. Simply select the first digit of the 2-digit year with the left menu, and the second digit with the right menu. You'll automatically see how the calculations below are affected by each change.
Starting year: 75
Partition: 72 + 3
Modify & solve: 36 - 3 = 33
Cast out 7s: 33 - 28 = 5
Note that years which are evenly divisible by 4 are easy to calculate. You'll quickly learn that multiples of 4 allow you to skip the partitioning step, and go straight to dividing a single number by 2.
Also, pay particular attention to the years 01, 02, 03, and 07. When these are partitioned, divided, and subtracted, they all result in negative numbers. In these few cases, you need to add 7 to make them positive. If you can remember that -1 + 7 = 6, -2 + 7 = 5, and -3 + 7 = 4, you can handle all of these situations.
The number you calculated from the year above will now be modified to take the century into account. Adjusting for the century only requires a little memory and a single addition.
If the requested century is in the 1700s, you don't need to add anything. For the 1800s, you'll add 2 to your running total. For the 1900s, you'll add 4, and for the 2000s, you'll add 5. For years after that, the pattern repeats every 400 years:
+ 0
+ 2
+ 4
+ 5
---
---
1500
1600
1700
1800
1900
2000
2100
2200
2300
2400
This table only goes back to 1500 because the calendar we currently use, the Gregorian calendar, was first adopted on October 15, 1582. In later lessons, you'll learn how to handle earlier dates.
To help you recall the right number, remember the nonsense mnemonic, No tuna for Friday. No represents +0, tuna represents +2, for represents +4, and Friday represents +5, since Friday is the 5th and last day of the traditional 5-day Monday through Friday work week.
How do you know which numbers go with which years? From right to left, they cover the 1700s, the 1800s, the 1900s, and the 2000s respectively. Bob Goddard (see Credits & Notes below) suggesting remembering that the mnemonics apply to the first 400 years of American history.
Once you can recall which modification goes with which year, you simply add the appropriate number for the century. Don't forget to cast out 7s if you get a number that's 7 or larger.
Going back to our 1975 example from above, we worked out a key number of 5 for 1975. To modify this number for the century, we add 4 for the 1900s, so 5 + 4 = 9. Casting out 7s, we subtract 9 - 7 = 2. So, 2 is our final key number for 1975.
What about, say, 1776? 76 doesn't need to be partitioned, since it's a multiple of 4. 76 ÷ 2 = 38, and casting out 7s we get 38 - 35 = 3. Since the 1700s have a century modification of +0, we simply don't add anything, and leave the total as 3. So, the year key for 1776 is 3.
Once you have this year key, what do you do with it? The next step is to take the key number you just calculated, and combine it with a particular month. You'll learn how to do that in the next tab.
Credits & Notes
The mathematical method for handling the 2-digit year comes directly from an article titled, How to find the day of the week on which any particular date falls by E. Rogent and W.W. Durbin in the August 1927 issue of The Linking Ring.
Now that you've calculated a key number based on the year and century, which will be treated as a date from here on out. The next step is to ask for a month. Each month is associated with a day of the week, and all you'll do to create the correct calendar for the month is to put the date you calculated from the year and century together with the day associated with the given month!
Months and Days
To help you recall with days are associated with which months, I developed 7 short rhymes to help make the connections memorable:
February, March, and November,
Three on Sunday to remember.
February, March, and November are all associated with Sunday. Sunday also happens to be the only day of the week associated with 3 different months. Each of the other days is associated with only 1 or 2 months each.
June day?
Moon-day!
This short rhyme makes it easy to remember that June is associated with Monday.
A skeptic needs clues,
but Sept./Dec. needs Tues.
Sept. is Septemeber, and Dec. is short for December, and they're both associated with Tues., or Tuesday.
Winds in April, Winds in July,
“Winds”-day’s the day, wet or dry.
This is simple enough. April and July are associated with Wednesday.
Jan’s and October’s 31,
Reminds us that Thursday won.
Jan, of course, refers to January. Not only are January and October both associated with Thursday, but they're the only set of months in a group which all happen to share the same length.
Month 5 is May,
Day 5 is Friday.
May being associate with Friday made for an easy rhyme, of course. Since May actually rhymes with every day of the week, I thought the additional association of the 5th month and the 5th and final day of the work week strengthened the association.
August’s few holidays make you yearn,
For the day off named after Saturn.
In most English-speaking countries, August tends to be the month with the fewest nation-wide holidays. This made for an interesting rhyme to help you memorize that August is associated with Saturn-day, or Saturday.
Leap Year Exceptions
Leap years stand out in this method because they don't need partitioning like most other numbers. If you're given a leap year, work out the key as taught previously, and then make a mental note that it's a leap year.
January and February both change the days with which they are associated in leap years. January in a leap year moves 1 day back from Thursday to Wednesday. In other words, in a leap year, January, April, and July are all associated with Wednesday, and October is the only month associated with Thursday.
Similarly, February also moves 1 day back from Sunday to Saturday in a leap year. In leap years, then, February and August are both associated with Saturday, and only March and November are associated with Sunday.
These two leap year exceptions may seem difficult to manage at first, but if you just think of January and February moving their day associations back by 1 day, it quickly becomes natural.
Remember that any year which is evenly divisible by 4 is a leap year, except for years ending in 00. Years ending in 00 are only leap years if they're evenly divisible by 400. For example, 2000 was a leap year, but 1900 and 2100 are not.
The approach of associating each year and century with a date, and each month with a day of the week is also from How to find the day of the week on which any particular date falls by E. Rogent and W.W. Durbin in the August 1927 issue of The Linking Ring.
In the original article, however, Durbin and Rogent's month and day associations were based on dates in the 1800s. In order to make the math work properly with Bob Goddard's First Sunday Doomsday Algorithm, however, the month and date associations have been changed so that they're now based in the 1700s.
Since the month and day association have been changed, the rhymes for remembering each association are original with me.
Creating the Calendar
At this point, many calendar calculation methods would have you do one last calculation to work out the day of the week for the given date.
Since my goal here is to minimize the calculation, this step simply involves creating a calendar for the given month and year. Here's a PDF template for a set of blank calendars, sized for printing on the back of business cards. When you bring out a single one to use, it should appear like this:
This step is where all of your calculation and memory work come together. To show you how, let's say you ask for a year, and you're given 1982. As you write down 1982 in the Date section of the calendar, you run through the calculations in your head: 82 = 80 + 2, which becomes 40 - 2 = 38, cast out 7s so we have 3, add 4 for the 1900s, giving 7, casting out 7s, leaves us with 0. We now know 1982 is a 0 year.
For the month, we'll say that you're given April, which you should immediately associate with Wednesday (Remember? Wind in April...), as you write down April in the Date section.
At this point, you know that 1982 is a 0 year and April is associated with a Wednesday, yet the calendar looks like this:
Generally, the rule is to put the day of the week you recalled above the number you were given. If you have 5 and Monday, you'd put Monday directly above the 5 on the calendar. In this case, though, we have 0 and Wednesday, so what do you do?
Simple, think of the 0th of a month as being 1 week before the 7th. In the case of 0, you always put the day of the week above the 7. Since April is associated with Wednesday, we put the abbreviation Wed above the 7th, like this:
From here, it's easy to see the remaining days of the week should be placed:
Don't forget to give the month the correct number of days. In our example, April is a 30-day month, so we add a 29 and 30 in the bottom row:
At this point, you're done creating the calendar! If this was someone's birthday, and they were born on April 17, 1982, a quick look at the calendar is all you need to see that they were born on a Saturday. You can circle that date and the day of the week, and now they have a souvenir of their birthday, and your amazing calendar skills!
Another Leap Year Reminder
In the previous tab, you learned that when working with leap years, and you're given either January or February as the month, you need to move the day associate back by 1 day. Let's see how this works in practice.
For this example, we'll choose 1992 as the year. Multiples of 4 aren't partitioned, so we start with 92 ÷ 2 = 46, and cast out 7s (46 - 42) to get 4. Adding 4 for the 1900s to that, we get 8, and we cast out 7s to get 1. You've worked out that 1992 is a 1 year, and also realize you need to keep alert if they ask for January and February.
Continuing with this example, we'll imagine that February is chosen as the month. When you hear this, you need to recall 2 concepts. First, February is associated with Saturday in a leap year, and second, that a leap-year February has 29 days. Putting all that together, the resulting calendar should appear like this when finished:
Leap-year Januarys and Februarys are probably the worst-case scenario you'll face in this method. Once you're comfortable with those, you're ready to perform this feat.
Verification by the Spectators
For this feat to really be impressive, they need to know that the calendar you created is correct. In the past, this meant carrying around cumbersome almanacs. Today, though, the handiest and most convenient way is carry an internet-connected mobile device around.
They can verify it with any kind of search, but I usually have them point their browser to Wolfram|Alpha (http://www.wolframalpha.com). Once you have the calendar created, have them enter the year and month followed by the word calendar, and Wolfram|Alpha will generate the calendar for that month!
Over in the Quick Calendar Month Creation Quiz, you can practice creating calendars by clicking on the Calendar Quiz button. This quiz is different than the previous quizzes, however, as it opens up full-screen in a new window.
There are two pull-down menus near the top. By default, the one on the top-right reads Gregorian: 1700-2099, which are the years you'll probably want to start with when you're first learning this feat.
Clicking on this menu will bring up other selections, which are: Gregorian: 1582-9999, which tests on years in the current calendar, but in a much wider range (the first 2 items on the tips page can help here), Julian: 1 AD - 1582 AD, and Julian: 45 BC - 1 BC. You won't need to worry about these until you've read the next page.
To use this quiz, select a range from the top-right menu, and then click on the New Date button on the top-left of the screen. Down by the word Date:, at the bottom, a random year from the selected range will appear, followed shortly by a random month.
The days of the week towards the top of the screen can be scrolled left or right by using the left and right arrow keys on your keyboard, or by swiping them left or right, if you're using a mobile device. What you want to do is use this ability to scroll the days to align the key you calculated from the given year with the day you associate with the given month.
For example, if you're given 2014, and you quickly work out a key of 2, and then you're given the month of May, which is associated with Friday, you want to scroll the days left or right, so that Friday is right above the 2.
In order to make sure the number of days are right, you use the pull-down menu at the top-left of the screen, which defaults to 28 days. You can also select 29 days, 30 days, and 31 days, and the added days will appear in the bottom row. Continuing with our 2014 May example, you'd want to select 31 days, since that's the length of May, so that 29, 30, and 31 appear in the bottom row.
Once you're satisfied that you've created the month, click the Verify button at the top right to see whether you are correct. It can inform you whether the number of days in the month is wrong, whether the days aren't labeled correctly, or whether you got it correct. If nothing is correct, it will simply say, Oops. Try again, please.
To try again, simply click the New Date button, and you're given a brand new random year and month!
Once you're comfortable working with years in the Gregorian calendar, the next tab will show you how to handle years in the Julian calendar, all the way back to 45 B.C.!
Credits & Notes
Creating a calendar month as an alternative to doing calculations involving an individual date is an approach I developed when I created Day One. In fact, the calendar PDF linked in the top of this tab was originally developed for Day One.
The quiz seen here is also a modified version of the calendar quiz I originally developed and included with Day One.
Other countries didn't adopt the Gregorian calendar until later. Britain and its colonies, including America at the time, adopted it in 1752, jumping from the Julian date of September 2 to the Gregorian date of September 14 on the following day.
In the Julian calendar, leap years happened every 4 years, including years ending in 00. With the Gregorian calendar, years ending in 00 are only leap years if they were evenly divisible by 400. For example, 2000 was a leap year, but 1900 was not and 2100 will not be.
With this shifting ahead of days, and different leap year rules, you might think it would be difficult to account for this change in a calendar calculation. I have good news for you. If you want to calculate a Julian date with this method, it's astonishingly simple.
To adjust for a Julian date, the only modification you need to do concerns the century. Instead of using the 0-2-4-5 No tuna for Friday approach, simply add the century number itself, casting out 7s if needed.
For example, if someone asked about 1066, you would start with 66 just as before. 66 = 64 + 2, which is modified and solved as 32 - 2 = 30. Casting out 7s from 30 leaves 2. For the Julian calendar, we just add the century number (10): 2 + 10 = 12. Casting out 7s from 12 leaves us with 5.
Next, if someone asks for the month of October, we recall that October is associated with Thursday (Jan’s and October’s 31...), so we can create a Julian calendar month for October 1066, by starting with a Thursday the 5th. Yes, Wolfram|Alpha can verify Julian calendar dates, too.
As long as you don't accept dates in 1582 from October 5th to October 14th, you can now handle dates as far back as 1 A.D., and as far into the future as you like!
To practice creating calendar for Julian years and months from 1 A.D. to 1582 A.D., you can go the the Quick Calendar Month Creation Quiz page, and click on the Calendar Quiz button. When the Calendar Quiz opens, select Julian: 1 AD - 1582 AD from the top-right menu to practice these dates.
B.C. Dates
The Julian calendar was first put in place by Julius Caesar in 45 B.C., so wouldn't it be nice to handle those first few dates, as well?
The first thing to remember is that the calendar we use today went from 1 B.C. directly to 1 A.D., so there was no year 0.
Handling dates such as these only requires one additional adjustment. When given a B.C. date, subtract the year from 57, and then treat it like any other Julian year.
If you're asked to create a calendar in, say, 25 B.C., the first step is to subtract it from 57: 57 - 25 = 32. Now you can handle that as a Julian year. 32 doesn't need to be partitioned, so we just do 32 ÷ 2 = 16, and casting out 7s from 16 leaves 2. Since the century is effectively 0, we just leave the key at 2.
Now, if someone asks for June, we recall that June is associated with a Monday (June day? Moon-day!), so June in 25 B.C. must've had a Monday the 2nd, which Wolfram|Alpha verifies for us!
When dealing with Julian and/or B.C. dates, don't forget the leap year adjustment, if needed. For example, since 25 B.C. is a leap year, you'd still work out that the key number for it is 2, but if someone asked for January, you need to recall that it's associated with Wednesday in a leap year. That way, you know January in 25 B.C. had a Wednesday the 2nd.
You can also practice BC dates by going to the Quick Calendar Month Creation Quiz page, and clicking on the Calendar Quiz button. After the Calendar Quiz opens, select Julian: 45 BC - 1 BC from the top-right menu to practice these dates.
Once you're comfortable working with Julian calendars and calendars back to 45 B.C., check out these tips to help your performance along.
Credits & Notes
The Julian and B.C. date modifications both come directly from the approach used in Bob Goddard's First Sunday Doomsday Algorithm. Basing the Gregorian century modifications on the 1700s is what makes this possible.
Tips
• Only the last 4 digits of a year matter. Working with the year 15739562 is no different than working with the year 9562.
• Another way to think about the centuries, especially when dealing with years far away from the 1700s, 1800s, 1900s, and 2000s:
If it's divisible by 400, like the 2000s, add 5.
If it's even, but not evenly divisible by 400, like the 1800s, add 2.
If it's just after a multiple of 400, like the 1700s, don't add anything.
If it's just before a multiple of 400, like the 1900s, add 4.
• If you're comfortable with using the Mnemonic Major System, you can speed up this feat even further. Since dates within a century repeat in a pattern every 28 years, all you have to do is memorize the 2-digit year keys for the years 00-27. You not only have quick recall of those years, but of all the other years as well:
Years ending in 28 through 55: Subtract 28, then recall the corresponding key.
Years ending in 56 through 83: Subtract 56, then recall the corresponding key.
Years ending in 84 through 99: Subtract 84, then recall the corresponding key.
• You don't have to use the business card calendar PDF. Any calendar that allows you to display an entire month AND adjust which days go with which months will work. Some examples:
• There's a simple formula for working out how many days needed to be added to the Julian calendar to adjust it to the Gregorian calendar. You can learn it from my Changing Calendars Mentally post. When working with the Julian calendar, this can make an impressive additional detail.
• Which months have a Friday the 13th? Once you've taken the year and century into account and you have your key number, ask yourself which day of the week is that many days after Saturday, and then ask yourself which months are associated with that day of the week. The months will be the only ones with a Friday the 13th!
For example, if you're given a year whose key you calculate as 3, ask yourself what day is 3 days after Saturday? The answer, of course, is Tuesday. Which months are associated with Tuesday? September and December are associated with that day, so you can state that September and December are the only months that year with a Friday the 13th!
This makes an impressive extra feat to add in to your performance. Note: As always, don't forget that January's and February's associations move 1 day back in leap years!
• What do you do if someone asks for a year before 45 B.C.? Explain that the pre-Julian Roman calendars were just too different. For example, one version had only 304 days each year, and another had 355 days each year, with leap years making some years as long as 378 days. The last pre-Julian year, 46 B.C., was adjusted to 445 days long!
• Hans-Christian Solka, author of the Day of Week Calculation Blog, also suggests the following related online resources for further reading:
While there are many mental math sites and videos freely available on the internet, very few seem to focus on division.
That's likely because division rarely comes out nice and neat, like addition, subtraction, and multiplication do. You have to deal with leftovers in the forms of remainders, fractions, or decimals.
Fractions are often seen as the most human-friendly way of expressing left-over numbers. Consequently, being able to give exact decimals, especially for unusual fractions such as 5/7 or 13/15, seems like an amazing feat to most people.
This tutorial will focus solely on division problems whose results are less than 1. For example, you'll learn how to deal with 5 ÷ 7 (or the equivalent fraction 5/7), but not how to deal with, say, 16 ÷ 7 (or 16/7).
When dealing with smaller divisors, such as those from 2 to 11, it's quite useful to have the decimal equivalents of all such problems less than 1 memorized.
You probably already know all the answers for dividing by 2 through 4 already:
Dividing by 5 is very easy. You just double the numerator, and put a decimal point in front of it:
1/5=.2
2/5=.4
3/5=.6
4/5=.8
You also already know how to divide most of the numbers by 6, as well:
2/6=1/3=.333...
3/6=1/2=.5
4/6=2/3=.666...
All you have to know is two more 6ths:
1/6=.1666...
5/6=.8333...
I'll come back to the 7th, but for now, I'm going to cover the 8ths, since they're not much more difficult than 4ths. The trick here is to multiply the numerator by 125, and stick the decimal point in front of it:
To be able to memorize every fraction/division problem up to dividing by 11, then, all most people need to learn is how to handle 7ths, 9ths, and 11ths.
9ths are especially easy, as you simply start with the decimal point, and repeat the numerator endlessly:
If you know your multiples of 9 up to 10, then you can handle 11ths. Simply multiply the numerator by 9, and express that as a 2-digit number (9 × 1 = 09). Repeat these 2 digits endlessly, and you've got your 11ths:
Finally, there's the 7ths. The 7ths have a very unusual pattern, starting with 1 ÷ 7:
1/7=.142857142857142857...
Notice that same sequence of numbers, 142857, repeats over and over again. To make things even easier, every 7th has this same repeating pattern. The only thing that changes is which number comes immediately after the decimal point. Here are the 7ths:
To determine which number comes first, simply multiply the numerator by 14, and note the digit in the 10s place. That will be the digit that comes first. For example, with 3/7ths, you'd do 3 × 14 = 42, and since 4 is the digit in the tens place, you'd start the pattern with 4, giving you .42857142857... and so on.
Dividing a 2-digit number by 100 is easy, of course. Take the numerator, place the decimal point in front of it, and you're done. 46/100? .46! 67/100? .67!
Dividing by 99
Surprisingly, dividing a 2-digit number by 99 is almost as easy as dividing by 100. The only difference is that the numerator repeats without end. 46/99? .464646...! 67/99? It's .676767...!
Think of 99 as being like 100, but since the 9s repeat, so does the numerator.
Dividing by 90
The technique for dividing any number from 1 to 89 by 90 takes us back to grade school math. Remember learning long division and getting answers like 3 remainder 7? That's the type of thinking you'll need here.
To divide a 2-digit number by 90, just divide the numerator by 9, but work out the answer in the x remainder y format. Once you know that, x will be the first digit after the decimal point, and y repeats after that.
For example, let's work out 58 ÷ 90. Ask yourself, what is 58 divided by 9? Assuming your know your multiplication tables, you should think of it as 6 remainder 4. That means the decimal equivalent of 58 ÷ 90 is .6444....
Remember this trick for 90 by thinking of the way you divided by 9 when you had 0 knowledge of fractions.
To divide by 91, you start by multiplying the numerator by 11, and then subtract 1. This number will likely be 3 digits, but if it's only 2 digits, place a 0 in front of it (76, for example, becomes 076). Put a decimal point in front of this 3 digit number, and you've got the first 3 digits of your answer.
To get the next 3 digits of the answer, subtract each of the digits from the previous step from 9. At this point, the number will repeat with the same 6 digits forever.
As a full example, let's work out 44 ÷ 91. We multiply 44 by 11 to get 484, and subtract 1, so we have 483. The first 3 digits of the answer, then are .483. Next, we work out 9 (always) - 4 (first digit) to get 5. 9 - 8 (second digit) = 1 and 9 - 3 (third digit) = 6, so the next 3 digits are these answers, 5, 1, and 6. Putting that all together, and repeating those same 6 digits, the decimal comes to .483516483516....
If you think of the 6 digits in the answer as two 3-digit numbers that always add up to 999, (Such as 483 and 516 in our previous example) it makes this easier. Since 91 ends in 1 just like 11, it's easy to remember that the technique for dividing by 91 involves multiplying by 11.
Dividing by 98
98 has a particularly surprising pattern. To start, you begin with the numerator, adding a 0 in front if it's a 1-digit number, and keep doubling the number. For example, with 6 ÷ 98, we start with 06 after the decimal point and keep doubling:
There are two more rules you need to know for this technique. First, anytime your doubling sequence gives you a number of 49 or more, you need to add 1 before continuing. Second, when you continue the sequence, double that modified number, but only give the last two digits. Continues the sequence as if these last two digits were just another two digits in the sequence, remembering to follow both of these rules.
To make this clearer, let's work out 16 ÷ 98. We start the series as before:
16 32 64
Stop! That 64 is over 49, so we need to add 1, making it a 65:
16 32 65
From there, we double 65 to get 130, but remember the second rule, that we only include the final two digits, the 30:
16 32 65 30
From here, we continue as if 30 were just another 2-digit number in the sequence. The next number would be 60, which is more than 49, so we add 1:
Once you get the hang of these rules, you can carry out the decimal equivalent as far as you like. Remember the add 1 rule even when you're starting with a number equal to or more than 49. For 78 ÷ 98, you'd start by adding 1 to 78, and continue from there:
As with many things in life, simplifying before working on the problem is the first thing you should do. If you get a problem such as 25 ÷ 35, or a number like 25/35ths, reduce the problem by dividing both parts by the same number, and keep doing this until you make the two numbers as small as possible. When you realize this boils down to 5/7, you can use the 7ths technique to realize that this works out to .7142857....
Attempting to reduce the fraction or division problem should always be your first step, but sometimes you just can't reduce the problem to dividing to 2 through 11. This is where knowing how to divide by numbers near 100 comes in handy. See if you can make the problem larger, into one you're already familiar with.
Let's say you want to know the decimal equivalent of 11/25ths. You don't have a technique for handling 25ths, but if you scale both parts of the problem up so it reads as 44/100, then it's easily apparent that the answer is .44.
What about 13/15ths? Multiply both numbers by 6, and you get 78/90ths, which you should easily work out to .86666... using the strategies you've learned.
Similarly, dividing by 13 can be turned into dividing by 91 by multiplying times 7 (because 91= 13 × 7) and dividing by 33 becomes dividing by 99 just by multiplying by 3. You can also divide by 49 by scaling up by 2, which turns it into a problem of dividing by 98.
If you need to divide by 14, and you can't reduce it to 7ths, you can multiply both numbers by 7 to turn it into a problem of dividing by 98. 11/14ths won't reduce to 7ths, but will scale up to 77/98ths, or .7857142857....
Reduce AND Enlarge
Again, reducing should always be the first step, but sometimes enlarging the problem after reducing can help. For example, here's how to handle 24 ÷ 39. Both numbers are divisible by 3, so the same result can be obtained by reducing it to 8/13. We can then scale this problem up to 56/91, and work out that it's .6153846....
Using this approach, you'll be able to handle any problem involving dividing by 13, 14, 15, 18, 20, 25, 30, 45, 49, and 50. Often, you'll be able to handle many other numbers, as well. 26/28ths is the same as 13/14ths, and thus 91/98ths.
Estimate
Sometimes, however, you're stuck with a division problem or fraction such as 32/43rds. That won't reduce to anything, and scaling the 43rds up to 86ths or 129ths doesn't bring up any familiar divisors.
If you look closely, however, you can see that it's quite close to 33/44, or 3/4, so you can estimate that it's roughly .75. 32/43 works out to roughly .7441860, so you can see that this is a good guess.
Most lessons in estimating fractions, such as this video, focus on rounding to 0, ½, or 1, but if you can round to the nearest 3rd, 4ths and 5ths, your estimated answers will improve greatly.
I hope you've found this tutorial useful and enjoyable!